100=x^2+16

Solution for 100=x^2+16 equation:

100=x^2+16

We move all terms to the left:

100-(x^2+16)=0

We get rid of parentheses

-x^2-16+100=0

We add all the numbers together, and all the variables

-1x^2+84=0

a = -1; b = 0; c = +84;
Δ = b2-4ac
Δ = 02-4·(-1)·84
Δ = 336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{336}=\sqrt{16*21}=\sqrt{16}*\sqrt{21}=4\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{21}}{2*-1}=\frac{0-4\sqrt{21}}{-2}
=-\frac{4\sqrt{21}}{-2}
=-\frac{2\sqrt{21}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{21}}{2*-1}=\frac{0+4\sqrt{21}}{-2}
=\frac{4\sqrt{21}}{-2}
=\frac{2\sqrt{21}}{-1}
$